Overview
| Comment: | Add Day 2 input and solutions |
|---|---|
| Downloads: | Tarball | ZIP archive | SQL archive |
| Timelines: | family | ancestors | descendants | both | trunk |
| Files: | files | file ages | folders |
| SHA3-256: |
35dfec6e8d276550930d6f4dc055796b |
| User & Date: | joel on 2018-12-02 17:26:22 |
| Other Links: | manifest | tags |
Context
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2018-12-03
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| 20:27 | Add Day 3 input check-in: a68afe user: joel tags: trunk | |
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2018-12-02
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| 17:26 | Add Day 2 input and solutions check-in: 35dfec user: joel tags: trunk | |
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2018-12-01
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| 23:16 | Day 1 solutions (both parts) check-in: 6b74a1 user: joel tags: trunk | |
Changes
Added day02-input.txt version [b9a78c].
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Added day02.rkt version [200b66].
> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 |
#lang racket
(require rackunit)
(define input (file->lines "day02-input.txt"))
;; Returns hash table where keys are unique chars in str,
;; values are # of occurrences of that char in str
(define (check-id str)
(for/fold ([seen (hash)])
([c (in-list (string->list str))])
(hash-set seen c (add1 (hash-ref seen c 0)))))
;; Returns hash table where keys are numbers, values are counts of
;; how many ids in id-list that have a character that repeats exactly
;; [key] times
(define (id-counts id-list)
(for/fold ([counts (hash)])
([id (in-list id-list)])
(for/fold ([each-count counts])
([c (in-list (remove-duplicates (hash-values (check-id id))))])
(hash-set each-count c (add1 (hash-ref each-count c 0))))))
(define (day01-part1 id-list)
(define counts (id-counts id-list))
(* (hash-ref counts 2 0) (hash-ref counts 3 0)))
(module+ test
(define test-ids '("abcdef"
"bababc"
"abbcde"
"abcccd"
"aabcdd"
"abcdee"
"ababab"))
(check-equal? (day01-part1 test-ids) 12)
(check-equal? (day01-part1 input) 7533)) ; Correct answer for part 1
(define part2-example
'("abcde"
"fghij"
"klmno"
"pqrst"
"fguij"
"axcye"
"wvxyz"))
;; Returns a list of characters at positions where id1 and id2 match
(define (compare-box-ids id1 id2)
(define id1-chars (string->list id1))
(define id2-chars (string->list id2))
(filter identity (for/list ([i (in-range (length id1-chars))])
(if (equal? (list-ref id1-chars i) (list-ref id2-chars i))
(list-ref id1-chars i)
#f))))
(define (day02-part2 ids)
(define (is-match? comparison-chars)
(equal? (length comparison-chars) (sub1 (string-length (first ids)))))
(define matches
(filter is-match? (map (curry compare-box-ids (first ids)) (rest ids))))
(if (not (empty? matches)) (list->string (first matches)) (day02-part2 (rest ids))))
(module+ test
(check-equal? (day02-part2 part2-example) "fgij")
(check-equal? (day02-part2 input) "mphcuasvrnjzzkbgdtqeoylva")) ; Correct answer for part 2
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